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Updated 4.2

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Administrator 2022-05-18 10:51:21 +02:00
parent 7ecf4b944d
commit 8b341f2038
1 changed files with 5 additions and 4 deletions
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9
Lösung/Aufgabe 4.sql
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@ -21,14 +21,15 @@ bezüglich der Gesamtnährwerte dieser Menüs.
*/
SELECT Menuname,
GROUP_CONCAT(Produktname SEPARATOR ', ') AS 'Produkte',
SUM(Fett) AS 'Fett',
SUM(Kohlenhydrate) AS 'Kohlenhydrate',
SUM(Eiweiss) AS 'Eiweiss',
SUM(Brennwert) AS 'Brennwert'
SUM(Fett * N.Menge / 100) AS 'Fett',
SUM(Kohlenhydrate * N.Menge / 100) AS 'Kohlenhydrate',
SUM(Eiweiss * N.Menge / 100) AS 'Eiweiss',
SUM(Brennwert * N.Menge / 100) AS 'Brennwert'
FROM Menu
JOIN Menucontent M on Menu.MenuID = M.MenuID
JOIN Produkt P on M.ProduktID = P.ProduktID
JOIN Naehrwerte N on P.ProduktID = N.ProduktID
JOIN Menge M2 on P.ProduktID = M2.ProduktID
GROUP BY Menuname;